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Tried that but in my case it didn't go to codebehind. I triggered that click with another button. Quite obvious - they are asp buttons and do postback. My solution in the end was client side. I made input button with onlcick ="another_jquery_function()" to manage that val. Thanks for answer!

Muno
– Muno

2012-11-21 07:24:24 +00:00
Commented Nov 21, 2012 at 7:24

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Correct minor typos or mistakes
Clarify meaning without changing it
Add related resources or links
Always respect the author’s intent
Don’t use edits to reply to the author

create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
_italic_ or **bold**
indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
to make links (use https whenever possible)

<https://example.com>

[example](https://example.com)

<a href="https://example.com">example</a>

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