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TylerH
TylerH
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As was answered here - Deserialize JSON into C# dynamic object?

It's pretty simple using Json.NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

Or using Newtonsoft.Json.Linq :

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

It's pretty simple using Json.NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

Or using Newtonsoft.Json.Linq :

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

As was answered here - Deserialize JSON into C# dynamic object?

It's pretty simple using Json.NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

Or using Newtonsoft.Json.Linq :

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

As was answered here - Deserialize JSON into C# dynamic object?

It's pretty simple using Json.NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

Or using Newtonsoft.Json.Linq :

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;
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As was answered here - Deserialize JSON into C# dynamic object?Deserialize JSON into C# dynamic object?

It's pretty simple using Json.NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

Or using Newtonsoft.Json.Linq :

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

As was answered here - Deserialize JSON into C# dynamic object?

It's pretty simple using Json.NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

Or using Newtonsoft.Json.Linq :

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

As was answered here - Deserialize JSON into C# dynamic object?

It's pretty simple using Json.NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

Or using Newtonsoft.Json.Linq :

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;
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Maximillian Laumeister
Maximillian Laumeister
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As was answered here - Deserialize JSON into C# dynamic object?Deserialize JSON into C# dynamic object?

It's pretty simple using Json.NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

Or using Newtonsoft.Json.Linq :

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

As was answered here - Deserialize JSON into C# dynamic object?

It's pretty simple using Json.NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

Or using Newtonsoft.Json.Linq :

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

As was answered here - Deserialize JSON into C# dynamic object?

It's pretty simple using Json.NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;

Or using Newtonsoft.Json.Linq :

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }"); string name = stuff.Name; string address = stuff.Address.City;
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