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Mar 2, 2023 at 9:44 vote accept sineverba
Sep 3, 2013 at 15:52 answer added Daniel timeline score: 3
Sep 3, 2013 at 15:39 comment added Denys Séguret @sineverba if you like your solution, post it as answer and accept it.
Sep 3, 2013 at 15:39 comment added sineverba @Andrew Whitaker Solved with for (var k=0; k<chars.length; k++) { if ($.inArray(chars[k], SPECIAL_CHARS) > -1) { numberOfSpecialChars++; } }
Sep 3, 2013 at 15:35 history edited Denys Séguret
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Sep 3, 2013 at 15:25 answer added Denys Séguret timeline score: 3
Sep 3, 2013 at 15:24 comment added Andrew Whitaker $.inArray takes value, array, not two arrays.
Sep 3, 2013 at 15:23 comment added Vogel612 sorry to ask, but if you check for existance of any special-char, why not use regex?
Sep 3, 2013 at 15:21 history asked sineverba CC BY-SA 3.0