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Nov 12, 2022 at 4:50 history edited Peter Mortensen CC BY-SA 4.0
Active reading. Used more standard formatting (we have italics and bold on this platform).
May 26, 2016 at 10:15 review Suggested edits
May 26, 2016 at 11:01
S Oct 22, 2015 at 9:29 history suggested René Sackers CC BY-SA 3.0
Restructured the sentence of the note about using .detach() to be a little more clear.
Oct 22, 2015 at 9:11 review Suggested edits
S Oct 22, 2015 at 9:29
Jul 10, 2014 at 22:37 review Suggested edits
Jul 10, 2014 at 22:42
Feb 4, 2014 at 4:34 comment added John - Not A Number Sorry, but Andrew Hare's accepted answer is correct - the detach is unnecessary. Try it in Pixic's JSFiddle above - if you remove the detach calls it works exactly the same, i.e. it does a move, NOT a copy. Here's the fork with just that one change: jsfiddle.net/D46y5 As documented in the API: api.jquery.com/appendTo : "If an element selected this way is inserted into a single location elsewhere in the DOM, it will be moved into the target (not cloned) and a new set consisting of the inserted element is returned"
Dec 17, 2013 at 19:02 comment added paulscode Best answer. Accepted answer creates a copy, doesn't move the element like the question asks for.
S Nov 6, 2013 at 2:07 review Late answers
Nov 6, 2013 at 2:11
S Nov 6, 2013 at 2:07 review First posts
Nov 6, 2013 at 2:08
Nov 6, 2013 at 1:50 history answered Alejandro Illecas CC BY-SA 3.0