[Yes, I have read several answers to similar questions, but didn't really get the answer I'm looking for, so I'm going to ask my question anyway.]

In the code below, how can I place the methods setSecret and tellSecret in Secret's prototype while still maintaining access to the private instance variable _secret, and also producing the same output?

I tried this (see jsbin) which placed the methods in the prototype, but changed the output.

function Secret() { // ===== private ===== var _secret; // ===== public ===== this.setSecret = function (secret) { _secret = secret; }; this.tellSecret = function () { console.log(_secret); }; } var secretA = new Secret(); var secretB = new Secret(); secretA.setSecret("AAA"); secretB.setSecret("BBB"); setTimeout(function () { console.log("Secret A"); secretA.tellSecret(); console.log("Secret B"); secretB.tellSecret(); }, 1000); // ===== output ===== Secret A AAA Secret B BBB 

[Yes, I have read several answers to similar questions, but didn't really get the answer I'm looking for, so I'm going to ask my question anyway.]

In the code below, how can I place the methods setSecret and tellSecret in Secret's prototype while still maintaining access to the private instance variable _secret, and also producing the same output?

I tried this (see jsbin) which placed the methods in the prototype, but changed the output.

function Secret() { // ===== private ===== var _secret; // ===== public ===== this.setSecret = function (secret) { _secret = secret; }; this.tellSecret = function () { console.log(_secret); }; } var secretA = new Secret(); var secretB = new Secret(); secretA.setSecret("AAA"); secretB.setSecret("BBB"); setTimeout(function () { console.log("Secret A"); secretA.tellSecret(); console.log("Secret B"); secretB.tellSecret(); }, 1000); // ===== output ===== Secret A AAA Secret B BBB 

[Yes, I have read several answers to similar questions, but didn't really get the answer I'm looking for, so I'm going to ask my question anyway.]

In the code below, how can I place the methods setSecret and tellSecret in Secret's prototype while still maintaining access to the private instance variable _secret, and also producing the same output?

I tried this which placed the methods in the prototype, but changed the output.

function Secret() { // ===== private ===== var _secret; // ===== public ===== this.setSecret = function (secret) { _secret = secret; }; this.tellSecret = function () { console.log(_secret); }; } var secretA = new Secret(); var secretB = new Secret(); secretA.setSecret("AAA"); secretB.setSecret("BBB"); setTimeout(function () { console.log("Secret A"); secretA.tellSecret(); console.log("Secret B"); secretB.tellSecret(); }, 1000); // ===== output ===== Secret A AAA Secret B BBB 

[Yes, I have read several answers to similar questions, but didn't really get the answer I'm looking for, so I'm going to ask my question anyway.]

In the code below, how can I place the methods setSecret and tellSecret in Secret's prototype while still maintaining access to the private instance variable _secret, and also producing the same output?

I tried this (see jsbin) which placed the methods in the prototype, but changed the output.

function Secret() { // ===== private ===== var _secret; // ===== public ===== this.setSecret = function (secret) { _secret = secret; }; this.tellSecret = function () { console.log(_secret); }; } var secretA = new Secret(); var secretB = new Secret(); secretA.setSecret("AAA"); secretB.setSecret("BBB"); setTimeout(function () { console.log("Secret A"); secretA.tellSecret(); console.log("Secret B"); secretB.tellSecret(); }, 1000); // ===== output ===== Secret A AAA Secret B BBB