Revisions to How can I do a recursive find/replace of a string with awk or sed?

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edited Nov 5, 2024 at 15:26

The simplest way for me is

grep -rlrlZ oldtext . | xargs -0 sed -i 's/oldtext/newtext/g'

The simplest way for me is

grep -rl oldtext . | xargs sed -i 's/oldtext/newtext/g'

The simplest way for me is

grep -rlZ oldtext . | xargs -0 sed -i 's/oldtext/newtext/g'

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edited May 12, 2018 at 12:12

The simplest way for me is

grep -rl oldtext . | xargs sed -i 's/oldtext/newtext/g'

If your text includes the / path character you can substitute with another delimiter character like so:

grep -rl 'oldtext/' . | xargs sed -i 's|oldtext/|newtext/|g'

The simplest way for me is

grep -rl oldtext . | xargs sed -i 's/oldtext/newtext/g'

If your text includes the / path character you can substitute with another delimiter character like so:

grep -rl 'oldtext/' . | xargs sed -i 's|oldtext/|newtext/|g'

The simplest way for me is

grep -rl oldtext . | xargs sed -i 's/oldtext/newtext/g'

added 177 characters in body

edited Apr 25, 2018 at 14:44

The simplest way for me is

grep -rl oldtext . | xargs sed -i 's/oldtext/newtext/g'

If your text includes the / path character you can substitute with another delimiter character like so:

grep -rl 'oldtext/' . | xargs sed -i 's|oldtext/|newtext/|g'

The simplest way for me is

grep -rl oldtext . | xargs sed -i 's/oldtext/newtext/g'

The simplest way for me is

grep -rl oldtext . | xargs sed -i 's/oldtext/newtext/g'

If your text includes the / path character you can substitute with another delimiter character like so:

grep -rl 'oldtext/' . | xargs sed -i 's|oldtext/|newtext/|g'

answered Mar 13, 2014 at 17:05

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