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replaced http://stackoverflow.com/ with https://stackoverflow.com/

edited May 23, 2017 at 12:20

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I guess this thread might help you to understand the evaluation order in java: What are the rules for evaluation order in Java?What are the rules for evaluation order in Java?

The most important part of this problem is that the first = is the actual assignment. In java the index is always evaluated befor the asignment, therefor a[a[b]] is the fist one in the evaluation order. And at this point a[b] is 0.

I guess this thread might help you to understand the evaluation order in java: What are the rules for evaluation order in Java?

The most important part of this problem is that the first = is the actual assignment. In java the index is always evaluated befor the asignment, therefor a[a[b]] is the fist one in the evaluation order. And at this point a[b] is 0.

I guess this thread might help you to understand the evaluation order in java: What are the rules for evaluation order in Java?

The most important part of this problem is that the first = is the actual assignment. In java the index is always evaluated befor the asignment, therefor a[a[b]] is the fist one in the evaluation order. And at this point a[b] is 0.

answered Mar 25, 2014 at 11:31

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I guess this thread might help you to understand the evaluation order in java: What are the rules for evaluation order in Java?

The most important part of this problem is that the first = is the actual assignment. In java the index is always evaluated befor the asignment, therefor a[a[b]] is the fist one in the evaluation order. And at this point a[b] is 0.