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You can use the substringWithRange method. It takes a start and end String.Index.

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: str.startIndex, end: str.endIndex)) //"Hello, playground" 

To change the start and end index, use advance().

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: advance(str.startIndex, 2), end: advance(str.endIndex, -1))) //"llo, playgroun" 

You can also still use the NSString method with NSRange, but you have to make sure you are using an NSString like this:

let myNSString = str as NSString myNSString.substringWithRange(NSRange(location: 0, length: 3)) 

Note: as JanX2 mentioned, this second method is not safe with unicode strings.

You can use the substringWithRange method. It takes a start and end String.Index.

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: str.startIndex, end: str.endIndex)) //"Hello, playground" 

To change the start and end index, use advancedBy(n).

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: str.startIndex.advancedBy(2), end: str.endIndex.advancedBy(-1))) //"llo, playgroun" 

You can also still use the NSString method with NSRange, but you have to make sure you are using an NSString like this:

let myNSString = str as NSString myNSString.substringWithRange(NSRange(location: 0, length: 3)) 

Note: as JanX2 mentioned, this second method is not safe with unicode strings.

You can use the substringWithRange method. It takes a start and end String.Index.

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: str.startIndex, end: str.endIndex)) //"Hello, playground" 

To change the start and end index, use advance().

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: advance(str.startIndex, 2), end: advance(str.endIndex, -1))) //"llo, playgroun" 

You can also still use the NSString method with NSRange, but you have to make sure you are using an NSString like this:

let myNSString = str as NSString myNSString.substringWithRange(NSRange(location: 0, length: 3)) 

Note: as JanX2 mentioned, this method is not safe with unicode strings.

You can use the substringWithRange method. It takes a start and end String.Index.

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: str.startIndex, end: str.endIndex)) //"Hello, playground" 

To change the start and end index, use advance().

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: advance(str.startIndex, 2), end: advance(str.endIndex, -1))) //"llo, playgroun" 

You can also still use the NSString method with NSRange, but you have to make sure you are using an NSString like this:

let myNSString = str as NSString myNSString.substringWithRange(NSRange(location: 0, length: 3)) 

Note: as JanX2 mentioned, this second method is not safe with unicode strings.

Well first of all, you can still use the NSString method with NSRange, but you have to make sure you are using an NSString like this:

let myNSString = str as NSString myNSString.substringWithRange(NSRange(location: 0,length: 3)) 

I've had trouble with using Ranges on Swift strings as well. This is the best I've come up with:

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: str.startIndex, end: str.endIndex)) 

It runs fine, but I haven't figured out how use indices other than start and end.

There is a succ() and pred() method on String.Index which returns the index before or after itself, but they don't take any arguments so it seems like there's no easy way to select different indices.

str.substringWithRange(Range<String.Index>(start: str.startIndex.succ().succ(), end: str.endIndex)) // "llo, Playground" 

Here's the definition of String.Index:

extension String : Collection {  struct Index : BidirectionalIndex {  func succ() -> String.Index func pred() -> String.Index } var startIndex: String.Index { get } var endIndex: String.Index { get } subscript (i: String.Index) -> Character { get } func generate() -> IndexingGenerator<String> } 

You can use the substringWithRange method. It takes a start and end String.Index.

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: str.startIndex, end: str.endIndex)) //"Hello, playground" 

To change the start and end index, use advance().

var str = "Hello, playground" str.substringWithRange(Range<String.Index>(start: advance(str.startIndex, 2), end: advance(str.endIndex, -1))) //"llo, playgroun" 

You can also still use the NSString method with NSRange, but you have to make sure you are using an NSString like this:

let myNSString = str as NSString myNSString.substringWithRange(NSRange(location: 0, length: 3)) 

Note: as JanX2 mentioned, this method is not safe with unicode strings.