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I missed that OP wanted to return a list of the sku; I viewed that part as comments next to the result set, illustrating how each "count" value was derived. Other answers sufficiently demonstrate the use of the GROUP_CONCAT aggregate function.

spencer7593
– spencer7593

2014-06-24 19:06:55 +00:00
Commented Jun 24, 2014 at 19:06
this works perfectly, thank you. Actually I showed the breakdown for illustration to help explain my question. In reality the Group Concat would not be practical since the duplicates run into the thousands.

sdfor
– sdfor

2014-06-24 19:07:14 +00:00
Commented Jun 24, 2014 at 19:07
@sdfor: given that you didn't know how to return this resultset, I thought it would be helpful to give some commentary about how this works, rather than just posting a SQL statement, so that you (and future readers) will be able to apply the same pattern to a similar problem in the future. (And you will run into a limitation of the GROUP_CONCAT function.)

spencer7593
– spencer7593

2014-06-24 19:09:08 +00:00
Commented Jun 24, 2014 at 19:09

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