Timeline for JavaScript: String.indexOf(...) allowing regular-expressions?

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Oct 28, 2021 at 14:07	comment	added	Stan Sokolov		this code will not work if i is undefined (it is optional). So a bit more fool proof version with input check: regexIndexOf(text, re, i) { let idx = (i && i > 0) ? text.substr(i).search(re) : text.search(re); return idx < 0 ? idx : idx + (i?i:0); }
Feb 11, 2017 at 8:20	history	edited	Web_Designer	CC BY-SA 3.0	add regexp arg to function
Aug 10, 2014 at 22:11	comment	added	gkoberger		Great solution, however the output is a bit different. indexOf will return a number from the beginning (regardless of the offset), whereas this will return the position from the offset. So, for parity, you'll want something more like this: `function regexIndexOf(text, offset) { var initial = text.substr(offset).search(/re/); if(initial >= 0) { initial += offset; } return initial; }`
Jul 17, 2013 at 19:31	history	edited	Fabrício Matté	CC BY-SA 3.0	added 37 characters in body
May 27, 2012 at 20:40	history	edited	Jashwant	CC BY-SA 3.0	added 126 characters in body
Nov 8, 2008 at 3:01	comment	added	Glenn		str.substr(i).search(/re/)
Nov 7, 2008 at 22:17	comment	added	Pat		from the question: While String.search() takes a regexp as a parameter it does not allow me to specify a second argument!
Nov 7, 2008 at 22:11	history	answered	Glenn	CC BY-SA 2.5