I've very recently migrated to Python 3.5. This code was working properly in Python 2.7:

with open(fname, 'rb') as f: lines = [x.strip() for x in f.readlines()] for line in lines: tmp = line.strip().lower() if 'some-pattern' in tmp: continue # ... code 

But in 3.5, on the if 'some-pattern' in tmp: continue line, I get an error which says:

TypeError: a bytes-like object is required, not 'str' 

I was unable to fix the problem using .decode() on either side of the in, nor could I fix it using

 if tmp.find('some-pattern') != -1: continue 

What is wrong, and how do I fix it?

I've very recently migrated to Python 3.5. This code was working properly in Python 2.7:

with open(fname, 'rb') as f: lines = [x.strip() for x in f.readlines()] for line in lines: tmp = line.strip().lower() if 'some-pattern' in tmp: continue # ... code 

But in 3.5, on the if 'some-pattern' in tmp: continue line, I get an error which says:

TypeError: a bytes-like object is required, not 'str' 

I was unable to fix the problem using .decode() on either side of the in, nor could I fix it using

 if tmp.find('some-pattern') != -1: continue 

What is wrong, and how do I fix it?

I've very recently migrated to Python 3.5. This code was working properly in Python 2.7:

with open(fname, 'rb') as f: lines = [x.strip() for x in f.readlines()] for line in lines: tmp = line.strip().lower() if 'some-pattern' in tmp: continue # ... code 

After upgrading to 3.5, I'm getting the:

TypeError: a bytes-like object is required, not 'str'

The error is on the last line (the pattern search code).

I've tried using the .decode() function on either side of the statement and also tried:

if tmp.find('some-pattern') != -1: continue 

- to no avail.

I was able to resolve almost all Python 2-to-Python 3 issues quickly, but this little statement was bugging me.

I've very recently migrated to Python 3.5. This code was working properly in Python 2.7:

with open(fname, 'rb') as f: lines = [x.strip() for x in f.readlines()] for line in lines: tmp = line.strip().lower() if 'some-pattern' in tmp: continue # ... code 

But in 3.5, on the if 'some-pattern' in tmp: continue line, I get an error which says:

TypeError: a bytes-like object is required, not 'str' 

I was unable to fix the problem using .decode() on either side of the in, nor could I fix it using

 if tmp.find('some-pattern') != -1: continue 

What is wrong, and how do I fix it?