Yes, you can do it, but you have to find the position of the first string with string's find() member, and then replace with it's replace() member.

string s("hello $name"); size_type pos = s.find( "$name" ); if ( pos != string::npos ) { s.replace( pos, 5, "somename" ); // 5 = length( $name ) } 

If you are planning on using the Standard Library, you should really gt hold of a copy of the book The C++ Standard Library which covers all this stuff very well.

Yes, you can do it, but you have to find the position of the first string with string's find() member, and then replace with it's replace() member.

string s("hello $name"); size_type pos = s.find( "$name" ); if ( pos != string::npos ) { s.replace( pos, 5, "somename" ); // 5 = length( $name ) } 

If you are planning on using the Standard Library, you should really get hold of a copy of the book The C++ Standard Library which covers all this stuff very well.

Yes, you can do it, but you have to find the position of the first string with string's find() member, and then replace with it's replace() member.

string s("hello $name"); size_type pos = s.find( "$name" ); if ( pos != string::npos ) { s.replace( pos, 5, "somename" ); // 5 = length( $name ) } 

Yes, you can do it, but you have to find the position of the first string with string's find() member, and then replace with it's replace() member.

string s("hello $name"); size_type pos = s.find( "$name" ); if ( pos != string::npos ) { s.replace( pos, 5, "somename" ); // 5 = length( $name ) } 

If you are planning on using the Standard Library, you should really gt hold of a copy of the book The C++ Standard Library which covers all this stuff very well.