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Just to add a note, if you are using NextDouble() and don't want the lower bound to be zero. You multiply by the difference between the higher bound and the lower bound, then add the difference between the lower bound and zero. So for -1 to 1 double rDouble = (r.NextDouble()*2)-1.0;

Tom Heard
– Tom Heard

2013-10-28 20:03:50 +00:00
Commented Oct 28, 2013 at 20:03
4

Or a simplified double generator in the range of -1.0 and 1.0: Double randDoubleY = new Random().Next(-100, 100) / 100.0D;

AI Replacement Theory
– AI Replacement Theory

2018-12-15 21:29:28 +00:00
Commented Dec 15, 2018 at 21:29
1

Random() uses a time-dependent seed, but writing that out explicitly is better for readability.

Evgeni Sergeev
– Evgeni Sergeev

2019-03-10 05:50:40 +00:00
Commented Mar 10, 2019 at 5:50

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