Revisions to Upload image using jQuery, AJAX and PHP

added 234 characters in body

edited Dec 14, 2016 at 14:55

You need to populate your FormData() with your file data:

var formData = new FormData(); $.each($('pictureCapture')[0].files, function(key, value) { formData.append(key, value); });

Add change your contentType to multipart in your jQuery ajax call:

$.ajax({ ... data: formData, ... contentType: 'multipart/form-data', data: formData,  ...

You need to populate your FormData() with your file data:

var formData = new FormData(); $.each($('pictureCapture')[0].files, function(key, value) { formData.append(key, value); });

Add change your contentType to multipart in your jQuery ajax call:

contentType: 'multipart/form-data', data: formData,

You need to populate your FormData() with your file data:

var formData = new FormData(); $.each($('pictureCapture')[0].files, function(key, value) { formData.append(key, value); });

Add change your contentType to multipart in your jQuery ajax call:

$.ajax({ ... data: formData, ... contentType: 'multipart/form-data',   ...

added 234 characters in body

edited Dec 14, 2016 at 14:51

You need to populate your FormData() with your file data:

var formData = new FormData(); $.each($('pictureCapture')[0].files, function(key, value) { formData.append(key, value); });

Add thischange your contentType to multipart in your jQuery ajax call:

contentType: 'multipart/form-data', data: formData,

Add this to your jQuery ajax call:

contentType: 'multipart/form-data',

You need to populate your FormData() with your file data:

var formData = new FormData(); $.each($('pictureCapture')[0].files, function(key, value) { formData.append(key, value); });

Add change your contentType to multipart in your jQuery ajax call:

contentType: 'multipart/form-data', data: formData,

answered Dec 14, 2016 at 14:42

Add this to your jQuery ajax call:

contentType: 'multipart/form-data',

Return to Answer