Skip to main content

Return to Answer

Second iteration.
Source Link
Peter Mortensen
Peter Mortensen
  • 31.4k
  • 22
  • 110
  • 134

Python < 3.7

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(chunk_num_blocks*h.block_size), b''): h.update(chunk) return h.digest()

Python 3.8 and above

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: while chunk := f.read(chunk_num_blocks*h.block_size): h.update(chunk) return h.digest()

Original post

If you want a more Pythonic (no while True) way of reading the file, check this code:

import hashlib def checksum_md5(filename): md5 = hashlib.md5() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(8192), b''): md5.update(chunk) return md5.digest()

Note that the iter() function needs an empty byte string for the returned iterator to halt at EOF, since read() returns b'' (not just '').

Python < 3.7

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(chunk_num_blocks*h.block_size), b''): h.update(chunk) return h.digest()

Python 3.8 and above

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: while chunk := f.read(chunk_num_blocks*h.block_size): h.update(chunk) return h.digest()

Original post

If you want a more Pythonic (no while True) way of reading the file check this code:

import hashlib def checksum_md5(filename): md5 = hashlib.md5() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(8192), b''): md5.update(chunk) return md5.digest()

Note that the iter() function needs an empty byte string for the returned iterator to halt at EOF, since read() returns b'' (not just '').

Python < 3.7

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(chunk_num_blocks*h.block_size), b''): h.update(chunk) return h.digest()

Python 3.8 and above

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: while chunk := f.read(chunk_num_blocks*h.block_size): h.update(chunk) return h.digest()

Original post

If you want a more Pythonic (no while True) way of reading the file, check this code:

import hashlib def checksum_md5(filename): md5 = hashlib.md5() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(8192), b''): md5.update(chunk) return md5.digest()

Note that the iter() function needs an empty byte string for the returned iterator to halt at EOF, since read() returns b'' (not just '').

Removed meta information (this belongs in comments).
Source Link
Peter Mortensen
Peter Mortensen
  • 31.4k
  • 22
  • 110
  • 134

Below I've incorporated suggestion from comments. Thank you all!

Python < 3.7

Python < 3.7

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(chunk_num_blocks*h.block_size), b''): h.update(chunk) return h.digest()

Python 3.8 and above

Python 3.8 and above

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: while chunk := f.read(chunk_num_blocks*h.block_size): h.update(chunk) return h.digest()

Original post

Original post

If you want a more Pythonic (no while True) way of reading the file check this code:

import hashlib def checksum_md5(filename): md5 = hashlib.md5() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(8192), b''): md5.update(chunk) return md5.digest()

Note that the iter() function needs an empty byte string for the returned iterator to halt at EOF, since read() returns b'' (not just '').

Below I've incorporated suggestion from comments. Thank you all!

Python < 3.7

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(chunk_num_blocks*h.block_size), b''): h.update(chunk) return h.digest()

Python 3.8 and above

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: while chunk := f.read(chunk_num_blocks*h.block_size): h.update(chunk) return h.digest()

Original post

If you want a more Pythonic (no while True) way of reading the file check this code:

import hashlib def checksum_md5(filename): md5 = hashlib.md5() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(8192), b''): md5.update(chunk) return md5.digest()

Note that the iter() function needs an empty byte string for the returned iterator to halt at EOF, since read() returns b'' (not just '').

Python < 3.7

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(chunk_num_blocks*h.block_size), b''): h.update(chunk) return h.digest()

Python 3.8 and above

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: while chunk := f.read(chunk_num_blocks*h.block_size): h.update(chunk) return h.digest()

Original post

If you want a more Pythonic (no while True) way of reading the file check this code:

import hashlib def checksum_md5(filename): md5 = hashlib.md5() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(8192), b''): md5.update(chunk) return md5.digest()

Note that the iter() function needs an empty byte string for the returned iterator to halt at EOF, since read() returns b'' (not just '').

Lots of fixes
Source Link
edit approved Sep 17, 2021 at 9:29
Community Bot
edit approved Sep 17, 2021 at 9:29
Community Bot
  • 1
  • 1

Below I've incorporated suggestion from comments. Thank you alall!

pythonPython < 3.7

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(chunk_num_blocks*h.block_size), b''): h.update(chunk) return h.digest()

pythonPython 3.8 and above

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: while chunk := f.read(chunk_num_blocks*h.block_size): h.update(chunk) return h.digest()

originalOriginal post

ifIf you care aboutwant a more pythonicPythonic (no 'while True'while True) way of reading the file check this code:

import hashlib def checksum_md5(filename): md5 = hashlib.md5() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(8192), b''): md5.update(chunk) return md5.digest()

Note that the iter() funciter() function needs an empty byte string for the returned iterator to halt at EOF, since read()read() returns b'' b'' (not just '''').

Below I've incorporated suggestion from comments. Thank you al!

python < 3.7

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(chunk_num_blocks*h.block_size), b''): h.update(chunk) return h.digest()

python 3.8 and above

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: while chunk := f.read(chunk_num_blocks*h.block_size): h.update(chunk) return h.digest()

original post

if you care about more pythonic (no 'while True') way of reading the file check this code:

import hashlib def checksum_md5(filename): md5 = hashlib.md5() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(8192), b''): md5.update(chunk) return md5.digest()

Note that the iter() func needs an empty byte string for the returned iterator to halt at EOF, since read() returns b'' (not just '').

Below I've incorporated suggestion from comments. Thank you all!

Python < 3.7

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(chunk_num_blocks*h.block_size), b''): h.update(chunk) return h.digest()

Python 3.8 and above

import hashlib def checksum(filename, hash_factory=hashlib.md5, chunk_num_blocks=128): h = hash_factory() with open(filename,'rb') as f: while chunk := f.read(chunk_num_blocks*h.block_size): h.update(chunk) return h.digest()

Original post

If you want a more Pythonic (no while True) way of reading the file check this code:

import hashlib def checksum_md5(filename): md5 = hashlib.md5() with open(filename,'rb') as f: for chunk in iter(lambda: f.read(8192), b''): md5.update(chunk) return md5.digest()

Note that the iter() function needs an empty byte string for the returned iterator to halt at EOF, since read() returns b'' (not just '').

made the function accept any hashlib class, move the magic 128 as parameter.
Source Link
Piotr Czapla
Piotr Czapla
  • 26.8k
  • 26
  • 106
  • 123
added 653 characters in body
Source Link
Piotr Czapla
Piotr Czapla
  • 26.8k
  • 26
  • 106
  • 123
++ missing function signature
Source Link
edit approved Jun 13, 2014 at 20:49
kmonsoor
edit approved Jun 13, 2014 at 20:49
kmonsoor
  • 8.2k
  • 7
  • 43
  • 58
f.read() returns a byte string, so you need to pass an empty byte string to the iter() function in order to get it to halt at EOF
Source Link
edit approved Apr 6, 2012 at 20:02
Community Bot
edit approved Apr 6, 2012 at 20:02
Community Bot
  • 1
  • 1
it is `digest` not `digset`!
Source Link
Nemo
Nemo
  • 71.9k
  • 11
  • 125
  • 160
it is `digest` not `digset`!
Source Link
edit approved Jul 20, 2011 at 4:37
Ali
edit approved Jul 20, 2011 at 4:37
Ali
  • 19.9k
  • 25
  • 109
  • 142
Source Link
Piotr Czapla
Piotr Czapla
  • 26.8k
  • 26
  • 106
  • 123