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lang-py
replargument tore.subis a string, not a regex; applyingre.escapeto it doesn't make any sense in the first place.replargument is not a simple string, it is parsed. For instance,re.sub(r'(.)', r'\1', 'X')will returnX, not\1.replargument: stackoverflow.com/q/49943270/247696\\1that returnsX, not the fact the second argument is a regex. You could dore.sub(r'(.)', '\\1', 'X')to get the exact same result. As far as I know, there is no reason to use a regex for the second argument. I could only assume it worked for you because it was using the string representation of the regex, andstr(r"\1") == "\\1".