Return to Answer

You can also use a list comprehension:

>>> newdict = {1:0, 2:0, 3:0} >>> [k for k in newdict.keys()] [1, 2, 3] 

You can also use a list comprehension:

>>> newdict = {1:0, 2:0, 3:0} >>> [k for k in newdict.keys()] [1, 2, 3] 

Or, shorter,

>>> [k for k in newdict] [1, 2, 3] 

Note: Order is not guaranteed on versions under 3.7 (ordering is still only an implementation detail with CPython 3.6).

you can also use  list comprehension !

>>> newdict = {1:0, 2:0, 3:0} >>> [k for k in newdict.keys()] [1, 2, 3] 

You can also use a list comprehension:

>>> newdict = {1:0, 2:0, 3:0} >>> [k for k in newdict.keys()] [1, 2, 3] 

So easy! just use list comprehension !

>>> newdict = {1:0, 2:0, 3:0} >>> [k for k in newdict.keys()] [1, 2, 3] 

you can also use list comprehension !

>>> newdict = {1:0, 2:0, 3:0} >>> [k for k in newdict.keys()] [1, 2, 3]