When I print the following
console.log('\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa6\xe0\xa4\xaf followed you') console.log(utf8.decode('\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa6\xe0\xa4\xaf followed you')) the result rightly is
थडथडदय followed you - (i) थडथडदय followed you - (ii) When I access a redis list using redis.lrange('notif-'+userId, 0, -1) its first element is displayed as
["\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa6\xe0\xa4\xaf followed you", "Users", "233", "some_url", 201, "Users"] (note that above is a list stored as a string in redis using redis.lpush('notif-'+userId, python-list), its the first item of a redis list)
Since the above can't be put into JSON.parse because of \x, I escape the slash and then revert using
let notificationList = JSON.parse(notificationParent.replace(/\\/g, '\\\\')) notification.text = notificationList[0].replace(/\\\\/g, '\\') Now, when I console.log(notification.text) and console.log(utf8.decode(notification.text)), what gets printed is
\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa6\xe0\xa4\xaf followed you \xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa6\xe0\xa4\xaf followed you What should I do to get results similar to (i) and (ii)?
EDIT: From the beginning, if I do the following
console.log(notificationParent) notificationParent = notificationParent.replace(/'/g, '"'); console.log(notificationParent) let notificationList = JSON.parse(notificationParent.toString()) console.log(notificationList) console.log(JSON.parse('["\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa6\xe0\xa4\xaf followed you", "Users", "233", "some_url", 201, "Users"]')) the result is
['\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa6\xe0\xa4\xaf followed you', 'Users', '233', 'https://storage.googleapis.com/humbee_images/cartoon-bee-1.jpg', 201, 'Users'] ["\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa5\xe0\xa4\xa1\xe0\xa4\xa6\xe0\xa4\xaf followed you", "Users", "233", "https://storage.googleapis.com/humbee_images/cartoon-bee-1.jpg", 201, "Users"] Syntax error: Unexpect token x in position 3 [ 'थडथडदय followed you', 'Users', '233', 'some_url', 201, 'Users' ] I don't understand the difference between the third and fourth print statement. Isnt the variable in 3rd containing the same string as 4th?
SOLVED: Joe's comment solved this puzzle. The second print although printing the variable with a single \ is actually double escaped, so the double escape needs to be converted by the replace function suggested in Joe's comment.