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edited Dec 28, 2018 at 22:53

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Try thisthe following code,. It works on all platforms:.

var break_for_winDOS = 'test\r\nwith\r\nline\r\nbreaks'; var break_for_linux = 'test\nwith\nline\nbreaks'; var break_for_older_mac = 'test\rwith\rline\rbreaks'; break_for_winDOS.replace(/(\r?\n|\r)/gm, ' '); //output 'test with line breaks' break_for_linux.replace(/(\r?\n|\r)/gm, ' '); //output 'test with line breaks' break_for_older_mac.replace(/(\r?\n|\r)/gm, ' '); //output Output 'test with line breaks'

Try this code, works on all platforms:

var break_for_winDOS = 'test\r\nwith\r\nline\r\nbreaks'; var break_for_linux = 'test\nwith\nline\nbreaks'; var break_for_older_mac = 'test\rwith\rline\rbreaks'; break_for_winDOS.replace(/(\r?\n|\r)/gm, ' '); //output 'test with line breaks' break_for_linux.replace(/(\r?\n|\r)/gm, ' '); //output 'test with line breaks' break_for_older_mac.replace(/(\r?\n|\r)/gm, ' '); //output 'test with line breaks'

Try the following code. It works on all platforms.

var break_for_winDOS = 'test\r\nwith\r\nline\r\nbreaks'; var break_for_linux = 'test\nwith\nline\nbreaks'; var break_for_older_mac = 'test\rwith\rline\rbreaks'; break_for_winDOS.replace(/(\r?\n|\r)/gm, ' '); //output 'test with line breaks' break_for_linux.replace(/(\r?\n|\r)/gm, ' '); //output 'test with line breaks' break_for_older_mac.replace(/(\r?\n|\r)/gm, ' '); // Output 'test with line breaks'

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answered Apr 28, 2017 at 21:21

Robson Morais Santos

Try this code, works on all platforms:

var break_for_winDOS = 'test\r\nwith\r\nline\r\nbreaks'; var break_for_linux = 'test\nwith\nline\nbreaks'; var break_for_older_mac = 'test\rwith\rline\rbreaks'; break_for_winDOS.replace(/(\r?\n|\r)/gm, ' '); //output 'test with line breaks' break_for_linux.replace(/(\r?\n|\r)/gm, ' '); //output 'test with line breaks' break_for_older_mac.replace(/(\r?\n|\r)/gm, ' '); //output 'test with line breaks'

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