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this does not work, it gives: Incorrect syntax near 'limit'.

v_emme
– v_emme

2017-05-30 08:10:04 +00:00
Commented May 30, 2017 at 8:10
This is because you tagged your question with MySQL, but it seems now that your database system is actually SQL Server, which is another product and their SQL dialects differ. I have updated my answer.

Thorsten Kettner
– Thorsten Kettner

2017-05-30 09:12:40 +00:00
Commented May 30, 2017 at 9:12

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Correct minor typos or mistakes
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create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
_italic_ or **bold**
indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
to make links (use https whenever possible)

<https://example.com>

[example](https://example.com)

<a href="https://example.com">example</a>

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