Revisions to How can I convert a Java 8 Stream to an Array?

Third iteration [<https://en.wiktionary.org/wiki/explanation#Noun>].

edited Oct 31 at 15:42

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You can convert a Java 8 stream to an array using this simple code block:

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

But let's explain things more. First, let's create a list of strings filled with three values:

String[] stringList = {"Bachiri", "Taoufiq", "Abderrahman"};

Create a stream from the given Array:

Stream<String> stringStream = Arrays.stream(stringList);

We can now perform some operations on this stream. For example:

Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());

And finally convert it to a Java 8 Array using these methods:

Classic method (functional interface)

 IntFunction<String[]> intFunction = new IntFunction<String[]>() { @Override public String[] apply(int value) { return new String[value]; } }; String[] myNewArray = myNewStream.toArray(intFunction);

Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

Method reference

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

Method reference Explanationexplanation:

It's another way of writing a lambda expression that it's strictly equivalent to the other.

You can convert a Java 8 stream to an array using this simple code block:

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

But let's explain things more. First, let's create a list of strings filled with three values:

String[] stringList = {"Bachiri","Taoufiq","Abderrahman"};

Create a stream from the given Array:

Stream<String> stringStream = Arrays.stream(stringList);

We can now perform some operations on this stream. For example:

Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());

And finally convert it to a Java 8 Array using these methods:

Classic method (functional interface)

 IntFunction<String[]> intFunction = new IntFunction<String[]>() { @Override public String[] apply(int value) { return new String[value]; } }; String[] myNewArray = myNewStream.toArray(intFunction);

Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

Method reference

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

Method reference Explanation:

It's another way of writing a lambda expression that it's strictly equivalent to the other.

You can convert a Java 8 stream to an array using this simple code block:

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

But let's explain things more. First, let's create a list of strings filled with three values:

String[] stringList = {"Bachiri", "Taoufiq", "Abderrahman"};

Create a stream from the given Array:

Stream<String> stringStream = Arrays.stream(stringList);

We can now perform some operations on this stream. For example:

Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());

And finally convert it to a Java 8 Array using these methods:

Classic method (functional interface)

 IntFunction<String[]> intFunction = new IntFunction<String[]>() { @Override public String[] apply(int value) { return new String[value]; } }; String[] myNewArray = myNewStream.toArray(intFunction);

Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

Method reference

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

Method reference explanation:

It's another way of writing a lambda expression that it's strictly equivalent to the other.

Second iteration. Used more standard formatting (as a result, the diff looks more extensive than it really is - use view "Side-by-side Markdown" to compare).

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edited Oct 31 at 14:45

Peter Mortensen

31.4k
22
110
134

You can convert a Java 8 stream to an array using this simple code block:

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

But let's explain things more. First, let's create a list of strings filled with three values:

String[] stringList = {"Bachiri","Taoufiq","Abderrahman"};

Create a stream from the given Array:

Stream<String> stringStream = Arrays.stream(stringList);

We can now perform some operations on this stream. For example:

Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());

And finally convert it to a Java 8 Array using these methods:

1-Classic method (functional interface)

IntFunction<String[]> intFunction = new IntFunction<String[]>() { @Override public String[] apply(int value) { return new String[value]; } }; String[] myNewArray = myNewStream.toArray(intFunction);

2 -Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

3- Method reference

String[] myNewArray3 = myNewStream.toArray(String[]::new);

Classic method (functional interface)

 IntFunction<String[]> intFunction = new IntFunction<String[]>() { @Override public String[] apply(int value) { return new String[value]; } }; String[] myNewArray = myNewStream.toArray(intFunction);

Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

Method reference

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

Method reference Explanation:

It's another way of writing a lambda expression that it's strictly equivalent to the other.

You can convert a Java 8 stream to an array using this simple code block:

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

But let's explain things more. First, let's create a list of strings filled with three values:

String[] stringList = {"Bachiri","Taoufiq","Abderrahman"};

Create a stream from the given Array:

Stream<String> stringStream = Arrays.stream(stringList);

We can now perform some operations on this stream. For example:

Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());

And finally convert it to a Java 8 Array using these methods:

1-Classic method (functional interface)

IntFunction<String[]> intFunction = new IntFunction<String[]>() { @Override public String[] apply(int value) { return new String[value]; } }; String[] myNewArray = myNewStream.toArray(intFunction);

2 -Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

3- Method reference

String[] myNewArray3 = myNewStream.toArray(String[]::new);

Method reference Explanation:

It's another way of writing a lambda expression that it's strictly equivalent to the other.

You can convert a Java 8 stream to an array using this simple code block:

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

But let's explain things more. First, let's create a list of strings filled with three values:

String[] stringList = {"Bachiri","Taoufiq","Abderrahman"};

Create a stream from the given Array:

Stream<String> stringStream = Arrays.stream(stringList);

We can now perform some operations on this stream. For example:

Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());

And finally convert it to a Java 8 Array using these methods:

Classic method (functional interface)

 IntFunction<String[]> intFunction = new IntFunction<String[]>() { @Override public String[] apply(int value) { return new String[value]; } }; String[] myNewArray = myNewStream.toArray(intFunction);

Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

Method reference

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

Method reference Explanation:

It's another way of writing a lambda expression that it's strictly equivalent to the other.

Active reading [<https://en.wikipedia.org/wiki/Java_%28programming_language%29> <https://english.stackexchange.com/questions/4645/is-it-ever-correct-to-have-a-space-before-a-question-or-exclamation#comment206109_4645> <https://en.wikipedia.org/wiki/Sentence_clause_structure#Run-on_sentences>].

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edited Oct 31 at 14:39

Peter Mortensen

31.4k
22
110
134

You can convert a javaJava 8 stream to an array using this simple code block:

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

But let's explain things more, first. First, let's Createcreate a list of stringstrings filled with three values:

String[] stringList = {"Bachiri","Taoufiq","Abderrahman"};

Create a stream from the given Array :

Stream<String> stringStream = Arrays.stream(stringList);

weWe can now perform some operations on this stream Ex. For example:

Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());

andAnd finally convert it to a javaJava 8 Array using these methods:

1-Classic method (Functionalfunctional interface)

IntFunction<String[]> intFunction = new IntFunction<String[]>() { @Override public String[] apply(int value) { return new String[value]; } }; String[] myNewArray = myNewStream.toArray(intFunction);

2 -Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

3- Method reference

String[] myNewArray3 = myNewStream.toArray(String[]::new);

Method reference Explanation:

It's another way of writing a lambda expression that it's strictly equivalent to the other.

You can convert a java 8 stream to an array using this simple code block:

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

But let's explain things more, first, let's Create a list of string filled with three values:

String[] stringList = {"Bachiri","Taoufiq","Abderrahman"};

Create a stream from the given Array :

Stream<String> stringStream = Arrays.stream(stringList);

we can now perform some operations on this stream Ex:

Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());

and finally convert it to a java 8 Array using these methods:

1-Classic method (Functional interface)

IntFunction<String[]> intFunction = new IntFunction<String[]>() { @Override public String[] apply(int value) { return new String[value]; } }; String[] myNewArray = myNewStream.toArray(intFunction);

2 -Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

3- Method reference

String[] myNewArray3 = myNewStream.toArray(String[]::new);

Method reference Explanation:

It's another way of writing a lambda expression that it's strictly equivalent to the other.

You can convert a Java 8 stream to an array using this simple code block:

 String[] myNewArray3 = myNewStream.toArray(String[]::new);

But let's explain things more. First, let's create a list of strings filled with three values:

String[] stringList = {"Bachiri","Taoufiq","Abderrahman"};

Create a stream from the given Array:

Stream<String> stringStream = Arrays.stream(stringList);

We can now perform some operations on this stream. For example:

Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());

And finally convert it to a Java 8 Array using these methods:

1-Classic method (functional interface)

IntFunction<String[]> intFunction = new IntFunction<String[]>() { @Override public String[] apply(int value) { return new String[value]; } }; String[] myNewArray = myNewStream.toArray(intFunction);

2 -Lambda expression

 String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);

3- Method reference

String[] myNewArray3 = myNewStream.toArray(String[]::new);

Method reference Explanation:

It's another way of writing a lambda expression that it's strictly equivalent to the other.

added 2 characters in body

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edited Jul 13, 2017 at 17:04

Bachiri Taoufiq Abderrahman

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answered May 25, 2017 at 16:57

Bachiri Taoufiq Abderrahman

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