Timeline for Remove all slashes and backsleshes
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 16, 2018 at 7:31 | vote | accept | Mikhail_Sam | ||
| Feb 16, 2018 at 7:31 | vote | accept | Mikhail_Sam | ||
| Feb 16, 2018 at 7:31 | |||||
| Feb 15, 2018 at 12:30 | comment | added | anubhava | @Mikhail_Sam: Previous answer also worked because it had separate \\ but I had wrong explanation. This one will also work because re.escape(symbolsToRemove) will escape each and every special character in symbolsToRemove string where \ is already present. | |
| Feb 15, 2018 at 12:28 | comment | added | Mikhail_Sam | I didn't get it - you previous answer did it well :) What's the matter to change it? | |
| Feb 15, 2018 at 12:27 | history | edited | anubhava | CC BY-SA 3.0 | deleted 89 characters in body |
| Feb 15, 2018 at 12:26 | comment | added | anubhava | Sorry for the goof up. Yes OP just needs to do re.esacpe | |
| Feb 15, 2018 at 12:22 | comment | added | Thierry Lathuille | Yes, it does: >>> string.punctuation '!"#$%&\'()*+,-./:;<=>?@[\\]^_{|}~'` | |
| Feb 15, 2018 at 12:17 | history | answered | anubhava | CC BY-SA 3.0 |