Revisions to Remove sublist from list

added 12 characters in body

edited Dec 10, 2020 at 11:28

Use sets:

C = list(set(A) - set(B))

In case you want to mantain duplicates and/or oder:

filter_set = set(B) C = [x for x in A if x not in filter_set]

Use sets:

C = list(set(A) - set(B))

In case you want to mantain duplicates:

filter_set = set(B) C = [x for x in A if x not in filter_set]

Use sets:

C = list(set(A) - set(B))

In case you want to mantain duplicates and/or oder:

filter_set = set(B) C = [x for x in A if x not in filter_set]

added 117 characters in body

edited Apr 9, 2018 at 16:41

Use sets:

C = list(set(A) - set(B))

In case you want to mantain duplicates:

filter_set = set(B) C = [x for x in A if x not in filter_set]

Use sets:

C = list(set(A) - set(B))

Use sets:

C = list(set(A) - set(B))

In case you want to mantain duplicates:

filter_set = set(B) C = [x for x in A if x not in filter_set]

answered Apr 9, 2018 at 16:39

Use sets:

C = list(set(A) - set(B))

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