Revisions to How can I find the index for a given item in a list?

deleted 8 characters in body

edited Jan 30, 2019 at 17:36

Finding index of item xx in list LL:

idx = L.index(x) if (x in L) else -1

Finding index of item x in list L:

idx = L.index(x) if (x in L) else -1

Finding index of item x in list L:

idx = L.index(x) if (x in L) else -1

deleted 61 characters in body

edited May 31, 2018 at 22:46

The simplest way to get theFinding index while handling the possibility of item x not being in list L:

idx = L.index(x) if (x in L) else -1

The simplest way to get the index while handling the possibility of item x not being in list L:

idx = L.index(x) if (x in L) else -1

Finding index of item x in list L:

idx = L.index(x) if (x in L) else -1

added 2 characters in body

edited May 28, 2018 at 20:55

pythonicThe simplest way to get the index while handling the possibility of item x not being in list L:

idx = L.index(x) if (x in L) else -1

pythonic way to get the index while handling the possibility of item x not being in list L:

idx = L.index(x) if (x in L) else -1

The simplest way to get the index while handling the possibility of item x not being in list L:

idx = L.index(x) if (x in L) else -1

deleted 4 characters in body

edited May 27, 2018 at 1:06

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answered May 25, 2018 at 21:56

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