Timeline for How to get only the name of the path with python? [duplicate]
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Jun 11, 2022 at 3:31 | history | suggested | tiger | CC BY-SA 4.0 | formatting names of varibles for clarity and fixed minor typo |
| Jun 10, 2022 at 14:12 | review | Suggested edits | |||
| S Jun 11, 2022 at 3:31 | |||||
| Feb 2, 2022 at 22:24 | history | left closed in review | BrokenBenchmark blackgreen♦ Perry | Original close reason(s) were not resolved | |
| Feb 2, 2022 at 5:33 | review | Reopen votes | |||
| Feb 2, 2022 at 22:24 | |||||
| Apr 12, 2019 at 19:53 | comment | added | user15741 | Ignore all of those old answers for python 2.x on the question from 2009. Use pathlib. | |
| Jun 15, 2018 at 13:47 | answer | added | mroman | timeline score: 2 | |
| Jun 15, 2018 at 13:46 | comment | added | pstatix | os.path.splitext(os.path.basename(a))[0] | |
| Jun 15, 2018 at 13:46 | history | closed | eyllanesc python Users with the python badge or a synonym can single-handedly close python questions as duplicates and reopen them as needed. | Duplicate of How do I get the filename without the extension from a path in Python? | |
| Jun 15, 2018 at 13:45 | answer | added | smheidrich | timeline score: 365 | |
| Jun 15, 2018 at 13:45 | answer | added | Martijn Pieters | timeline score: 19 | |
| Jun 15, 2018 at 13:45 | comment | added | BoarGules | Hint: look in module os.path | |
| Jun 15, 2018 at 13:44 | comment | added | Martijn Pieters | Just to be clear, you want the final part without the extension? | |
| Jun 15, 2018 at 13:44 | history | edited | Martijn Pieters | CC BY-SA 4.0 | edited tags |
| Jun 15, 2018 at 13:42 | history | asked | user9860026 | CC BY-SA 4.0 |