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improved formatting
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edit approved Apr 22, 2019 at 21:46
Community Bot
edit approved Apr 22, 2019 at 21:46
Community Bot
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You can use the following. In this case of last character it's an overkill but for a substring, its useful:

`varvar word = "linto.yahoo.com.";`"; `varvar last = ".com.";`"; `ifif (word.substr(-(last.length)) == last)`  `alertalert("its a match");` ;

You can use the following. In this case of last character it's an overkill but for a substring, its useful:

`var word = "linto.yahoo.com.";` `var last = ".com.";` `if (word.substr(-(last.length)) == last)`  `alert("its a match");`

You can use the following. In this case of last character it's an overkill but for a substring, its useful:

var word = "linto.yahoo.com."; var last = ".com."; if (word.substr(-(last.length)) == last) alert("its a match");
added 6 characters in body
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Eray Balkanli
Eray Balkanli
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You can use the following. In this case of last character it's an overkill but for a substring, its useful:
var word = "linto.yahoo.com."; var last = ".com."; if (word.substr(-(last.length)) == last)
alert("its a match");

`var word = "linto.yahoo.com.";` `var last = ".com.";` `if (word.substr(-(last.length)) == last)` `alert("its a match");`

You can use the following. In this case of last character it's an overkill but for a substring, its useful:
var word = "linto.yahoo.com."; var last = ".com."; if (word.substr(-(last.length)) == last)
alert("its a match");

You can use the following. In this case of last character it's an overkill but for a substring, its useful:

`var word = "linto.yahoo.com.";` `var last = ".com.";` `if (word.substr(-(last.length)) == last)` `alert("its a match");`
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Gauravsa
Gauravsa
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You can use the following. In this case of last character it's an overkill but for a substring, its useful:
var word = "linto.yahoo.com."; var last = ".com."; if (word.substr(-(last.length)) == last)
alert("its a match");