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The simplest solutions seem to overlook that UTC time will be used, including highly up-voted ones. Below is a streamlined, ES6, non-jQuery version of a couple of existing answers:

const today = (function() { const now = new Date(); const month = (now.getMonth() + 1).toString().padStart(2, '0'); const day = now.getDate().toString().padStart(2, '0'); return `${now.getFullYear()}-${month}-${day}`; })(); console.log(today); // as of posting this answer: 2019-01-24 

The simplest solutions seem to overlook that UTC time will be used, including highly up-voted ones. Below is a streamlined, ES6, non-jQuery version of a couple of existing answers:

const today = (function() { const now = new Date(); const month = (now.getMonth() + 1).toString().padStart(2, '0'); const day = now.getDate().toString().padStart(2, '0'); return `${now.getFullYear()}-${month}-${day}`; })(); console.log(today); // as of posting this answer: 2019-01-24 

The simplest solutions seem to overlook that UTC time will be used, including highly up-voted ones. Below is a streamlined, ES6, non-jQuery version of a couple of existing answers:

let today = (function() { let now = new Date(); let month = (now.getMonth() + 1).toString().padStart(2, '0'); let day = now.getDate().toString().padStart(2, '0'); return `${now.getFullYear()}-${month}-${day}`; })(); console.log(today); // as of posting this answer: 2019-01-24 

The simplest solutions seem to overlook that UTC time will be used, including highly up-voted ones. Below is a streamlined, ES6, non-jQuery version of a couple of existing answers:

const today = (function() { const now = new Date(); const month = (now.getMonth() + 1).toString().padStart(2, '0'); const day = now.getDate().toString().padStart(2, '0'); return `${now.getFullYear()}-${month}-${day}`; })(); console.log(today); // as of posting this answer: 2019-01-24 

The simplest solutions seem to overlook that UTC time will be used, including highly up-voted ones. Below is a streamlined, ES6, non-jQuery version of a couple of existing answers:

let today = (function() { let now = new Date(); let day = ("0" + now.getDate()).slice(-2); let month = ("0" + (now.getMonth() + 1)).slice(-2); return `${now.getFullYear()}-${month}-${day}`; })(); console.log(today); // as of posting this answer: 2019-01-24 

The simplest solutions seem to overlook that UTC time will be used, including highly up-voted ones. Below is a streamlined, ES6, non-jQuery version of a couple of existing answers:

let today = (function() { let now = new Date(); let month = (now.getMonth() + 1).toString().padStart(2, '0'); let day = now.getDate().toString().padStart(2, '0'); return `${now.getFullYear()}-${month}-${day}`; })(); console.log(today); // as of posting this answer: 2019-01-24