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1

@user1810100 mentioned essentially that almost exactly 5 years to the day before you posted this...

John
– John

2019-03-12 18:50:44 +00:00
Commented Mar 12, 2019 at 18:50
1

Adding an if s.find("ZZZ") > s.find("AAA"): to it, avoids issues if 'ZZZ` isn't in the string, which would return '1234uuijjk'

Rolf of Saxony
– Rolf of Saxony

2020-11-14 20:42:42 +00:00
Commented Nov 14, 2020 at 20:42
@tzot's answer (stackoverflow.com/a/4917004/358532) with partition instead of split seems more robust (depending on your needs), as it returns an empty string if one of the substrings isn't found.

Yann Dìnendal
– Yann Dìnendal

2021-09-16 15:33:02 +00:00
Commented Sep 16, 2021 at 15:33

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create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
_italic_ or **bold**
indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
to make links (use https whenever possible)

<https://example.com>

[example](https://example.com)

<a href="https://example.com">example</a>

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