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Used a more direct cross reference (as user names can change at any time).

edited Oct 28, 2022 at 11:47

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I don't like loops. Based on @Nathan FegerNathan Feger's answer:

md5 = hashlib.md5() with open(filename, 'rb') as f: functools.reduce(lambda _, c: md5.update(c), iter(lambda: f.read(md5.block_size * 128), b''), None) md5.hexdigest()

I don't like loops. Based on @Nathan Feger:

md5 = hashlib.md5() with open(filename, 'rb') as f: functools.reduce(lambda _, c: md5.update(c), iter(lambda: f.read(md5.block_size * 128), b''), None) md5.hexdigest()

I don't like loops. Based on Nathan Feger's answer:

md5 = hashlib.md5() with open(filename, 'rb') as f: functools.reduce(lambda _, c: md5.update(c), iter(lambda: f.read(md5.block_size * 128), b''), None) md5.hexdigest()

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answered May 8, 2019 at 10:48

Sebastian Wagner

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I don't like loops. Based on @Nathan Feger:

md5 = hashlib.md5() with open(filename, 'rb') as f: functools.reduce(lambda _, c: md5.update(c), iter(lambda: f.read(md5.block_size * 128), b''), None) md5.hexdigest()

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