Revisions to Alternative for __dirname in Node.js when using ES6 modules

added 131 characters in body

edited Oct 10, 2019 at 20:09

The simplest answer is:As Geoff pointed out the following code returns not the module's path but working directory.

import path from 'path'; const __dirname = path.resolve();

works with --experimental-modules

The simplest answer is:

import path from 'path'; const __dirname = path.resolve();

works with --experimental-modules

As Geoff pointed out the following code returns not the module's path but working directory.

import path from 'path'; const __dirname = path.resolve();

works with --experimental-modules

deleted 10 characters in body

edited Sep 20, 2019 at 10:04

I believe theThe simplest answer is:

import path from 'path'; const __dirname = path.resolve();

works with --experimental-modules

I believe the simplest answer is:

import path from 'path'; const __dirname = path.resolve();

works with --experimental-modules

The simplest answer is:

import path from 'path'; const __dirname = path.resolve();

works with --experimental-modules

answered Sep 17, 2019 at 10:24

I believe the simplest answer is:

import path from 'path'; const __dirname = path.resolve();

works with --experimental-modules

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