I want Django to display an image when accessed. For example, I want to display only the image as a response, such as when accessing the image below. And I want to do the url as a normal URL without using .jpeg or .png.

sample

But now, no matter what method you try, it doesn't work.

from django.http import HttpResponse import os from django.core.files import File import codecs def image(request): file_name = os.path.join( os.path.dirname(__file__), '12.jpg' ) try: with open(file_name, "rb") as f: a = f.read() return HttpResponse(a, content_type="image/jpeg") except IOError: red = Image.new('RGBA', (1, 1), (255, 0, 0, 0)) response = HttpResponse(content_type="image/jpeg") red.save(response, "JPEG") return response urlpatterns = [ url('image', image) ] 

With the above code, the following error occurs.

'utf-8' codec can't decode byte 0xff in position 0: invalid start byte 

I want Django to display an image when accessed. For example, I want to display only the image as a response, such as when accessing the image below. And I want to do the URL as a normal URL without using .jpeg or .png.

Sample:

But now, no matter what method you try, it doesn't work.

from django.http import HttpResponse import os from django.core.files import File import codecs def image(request): file_name = os.path.join( os.path.dirname(__file__), '12.jpg' ) try: with open(file_name, "rb") as f: a = f.read() return HttpResponse(a, content_type="image/jpeg") except IOError: red = Image.new('RGBA', (1, 1), (255, 0, 0, 0)) response = HttpResponse(content_type="image/jpeg") red.save(response, "JPEG") return response urlpatterns = [ url('image', image) ] 

With the above code, the following error occurs.

'utf-8' codec can't decode byte 0xff in position 0: invalid start byte