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I came here looking for an answer to this question. Didn't find it and ended up building this by repeated calls to .split(...) It isn't elegant but you can choose which delimiters are preserved and which aren't. There's probably a way to avoid the String <--> Substring conversions, anyone know?

I came here looking for an answer to this question. Didn't find what I was looking for and ended up building this by repeated calls to .split(...) It isn't elegant but you can choose which delimiters are preserved and which aren't. There's probably a way to avoid the String <--> Substring conversions, anyone know?

In the case above, the selectors are not in actual sets. I didn't need that, but if you do, simply make these declarations,

let preservedDelimiters: Set<Character> = [ "{", "}", "(", ")", "[", "]" ] let omittedDelimiters: Set<Character> = [ " ", "\n", ",", "." ] 

and replace the whereSeparator function with:

whereSeparator: { if preservedDelimiters.contains($0) { separator = $0 return true } else if omittedDelimiters.contains($0) { separator = " " return true } else { return false } } 

I came here looking for an answer to this question. Didn't find it and ended up building this by repeated calls to .split(...) It isn't elegant but you can choose which delimiters are preserved and which aren't. There's probably a way to avoid the String <--> Substring conversions, anyone know?

var input = """ {All those moments will be (lost in time)}, like tears [in rain](. ([(Time to)] die)) """ var separator: Character = "!" var output: [String] = [] repeat { let tokens = input.split( maxSplits: 1, omittingEmptySubsequences: false, whereSeparator: { switch $0 { case "{", "}", "(", ")", "[", "]": // preserve separator = $0; return true case " ", "\n", ",", ".": // omit separator = " "; return true default: return false } } ) if tokens[0] != "" { output.append(String(tokens[0])) } guard tokens.count == 2 else { break } if separator != " " { output.append(String(separator)) } input = String(tokens[1]) } while true for o in output { print("\(o)") } 

I came here looking for an answer to this question. Didn't find it and ended up building this by repeated calls to .split(...) It isn't elegant but you can choose which delimiters are preserved and which aren't. There's probably a way to avoid the String <--> Substring conversions, anyone know?

var input = """ {All those moments will be (lost in time)}, like tears [in rain](. ([(Time to)] die)) """ var separator: Character = "!" var output: [String] = [] repeat { let tokens = input.split( maxSplits: 1, omittingEmptySubsequences: false, whereSeparator: { switch $0 { case "{", "}", "(", ")", "[", "]": // preserve separator = $0; return true case " ", "\n", ",", ".": // omit separator = " "; return true default: return false } } ) if tokens[0] != "" { output.append(String(tokens[0])) } guard tokens.count == 2 else { break } if separator != " " { output.append(String(separator)) } input = String(tokens[1]) } while true for token in output { print("\(token)") }