I researched first and couldn't find an answer to my question. I am trying to run multiple functions in parallel in Python.

I have something like this:

files.py import common #common is a util class that handles all the IO stuff dir1 = 'C:\folder1' dir2 = 'C:\folder2' filename = 'test.txt' addFiles = [25, 5, 15, 35, 45, 25, 5, 15, 35, 45] def func1(): c = common.Common() for i in range(len(addFiles)): c.createFiles(addFiles[i], filename, dir1) c.getFiles(dir1) time.sleep(10) c.removeFiles(addFiles[i], dir1) c.getFiles(dir1) def func2(): c = common.Common() for i in range(len(addFiles)): c.createFiles(addFiles[i], filename, dir2) c.getFiles(dir2) time.sleep(10) c.removeFiles(addFiles[i], dir2) c.getFiles(dir2) 

I want to call func1 and func2 and have them run at the same time. The functions do not interact with each other or on the same object. Right now I have to wait for func1 to finish before func2 to start. How do I do something like below:

process.py from files import func1, func2 runBothFunc(func1(), func2()) 

I want to be able to create both directories pretty close to the same time because every min I am counting how many files are being created. If the directory isn't there it will throw off my timing.

I am trying to run multiple functions in parallel in Python.

I have something like this:

files.py import common #common is a util class that handles all the IO stuff dir1 = 'C:\folder1' dir2 = 'C:\folder2' filename = 'test.txt' addFiles = [25, 5, 15, 35, 45, 25, 5, 15, 35, 45] def func1(): c = common.Common() for i in range(len(addFiles)): c.createFiles(addFiles[i], filename, dir1) c.getFiles(dir1) time.sleep(10) c.removeFiles(addFiles[i], dir1) c.getFiles(dir1) def func2(): c = common.Common() for i in range(len(addFiles)): c.createFiles(addFiles[i], filename, dir2) c.getFiles(dir2) time.sleep(10) c.removeFiles(addFiles[i], dir2) c.getFiles(dir2) 

I want to call func1 and func2 and have them run at the same time. The functions do not interact with each other or on the same object. Right now I have to wait for func1 to finish before func2 to start. How do I do something like below:

process.py from files import func1, func2 runBothFunc(func1(), func2()) 

I want to be able to create both directories pretty close to the same time because every min I am counting how many files are being created. If the directory isn't there it will throw off my timing.

I researched first and couldn't find an answer to my question. I am trying to run multiple functions in parallel in Python.

I have something like this:

files.py import common #common is a util class that handles all the IO stuff dir1 = 'C:\folder1' dir2 = 'C:\folder2' filename = 'test.txt' addFiles = [25, 5, 15, 35, 45, 25, 5, 15, 35, 45] def func1(): c = common.Common() for i in range(len(addFiles)): c.createFiles(addFiles[i], filename, dir1) c.getFiles(dir1) time.sleep(10) c.removeFiles(addFiles[i], dir1) c.getFiles(dir1) def func2(): c = common.Common() for i in range(len(addFiles)): c.createFiles(addFiles[i], filename, dir2) c.getFiles(dir2) time.sleep(10) c.removeFiles(addFiles[i], dir2) c.getFiles(dir2) 

I want to call func1 and func2 and have them run at the same time. The functions do not interact with each other or on the same object. Right now I have to wait for func1 to finish before func2 to start. How do I do something like below:

process.py from files import func1, func2 runBothFunc(func1(), func2()) 

I want to be able to create both directories pretty close to the same time because every min I am counting how many files are being created. If the directory isn't there it will throw off my timing.

I researched first and couldn't find an answer to my question. I am trying to run multiple functions in parallel in Python.

I have something like this:

files.py import common #common is a util class that handles all the IO stuff dir1 = 'C:\folder1' dir2 = 'C:\folder2' filename = 'test.txt' addFiles = [25, 5, 15, 35, 45, 25, 5, 15, 35, 45] def func1(): c = common.Common() for i in range(len(addFiles)): c.createFiles(addFiles[i], filename, dir1) c.getFiles(dir1) time.sleep(10) c.removeFiles(addFiles[i], dir1) c.getFiles(dir1) def func2(): c = common.Common() for i in range(len(addFiles)): c.createFiles(addFiles[i], filename, dir2) c.getFiles(dir2) time.sleep(10) c.removeFiles(addFiles[i], dir2) c.getFiles(dir2) 

I want to call func1 and func2 and have them run at the same time. The functions do not interact with each other or on the same object. Right now I have to wait for func1 to finish before func2 to start. How do I do something like below:

process.py from files import func1, func2 runBothFunc(func1(), func2()) 

I want to be able to create both directories pretty close to the same time because every min I am counting how many files are being created. If the directory isn't there it will throw off my timing.

I researched first and couldn't find an answer to my question. I am trying to run multiple functions in parallel in Python.

Lets say I have something like this:

function.py def func1(): create directory add files def func2(): create different directory add files 

I want to call func1 and func2 and have them run at the same time. The functions do not interact with each other or on the same object. Right now I have to wait for func1 to finish before func2 to start. How do I do something like below:

process.py from function import func1, func2 runBothFunc(func1(), func2()) 

I want to be able to create both directories pretty close to the same time because every min I am counting how many files are being created. If the directory isn't there it will throw off my timing.

I researched first and couldn't find an answer to my question. I am trying to run multiple functions in parallel in Python.

I have something like this:

files.py import common #common is a util class that handles all the IO stuff dir1 = 'C:\folder1' dir2 = 'C:\folder2' filename = 'test.txt' addFiles = [25, 5, 15, 35, 45, 25, 5, 15, 35, 45] def func1(): c = common.Common() for i in range(len(addFiles)): c.createFiles(addFiles[i], filename, dir1) c.getFiles(dir1) time.sleep(10) c.removeFiles(addFiles[i], dir1) c.getFiles(dir1)  def func2(): c = common.Common()   for i in range(len(addFiles)):  c.createFiles(addFiles[i], filename, dir2) c.getFiles(dir2) time.sleep(10)  c.removeFiles(addFiles[i], dir2) c.getFiles(dir2) 

I want to call func1 and func2 and have them run at the same time. The functions do not interact with each other or on the same object. Right now I have to wait for func1 to finish before func2 to start. How do I do something like below:

process.py from files import func1, func2 runBothFunc(func1(), func2()) 

I want to be able to create both directories pretty close to the same time because every min I am counting how many files are being created. If the directory isn't there it will throw off my timing.