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1

Exactly. Both (object)foo1 == null or foo1 == (object)null will go to the built-in overload ==(object, object) and not to the user-defined overload ==(Foo, Foo). It is just like overload resolution on methods.

Jeppe Stig Nielsen
– Jeppe Stig Nielsen

2014-06-04 11:47:35 +00:00
Commented Jun 4, 2014 at 11:47
2

To future visitors - the accepted answer is a function, that executes the == of object. This is basically the same as the accepted answer, with one downside: It needs a cast. The accpeted answer is thus superior.

Mafii
– Mafii

2016-07-08 12:43:59 +00:00
Commented Jul 8, 2016 at 12:43
1

@Mafii The cast is purely a compile time operation. Since the compiler knows that the cast cannot fail, it need not check anything at runtime. The differences between the methods are completely aesthetic.

Servy
– Servy

2017-06-05 20:43:33 +00:00
Commented Jun 5, 2017 at 20:43

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