As mentioned elsewhere a possible issue with dct.get(key, default) is that, if key in dct but dct[key] is None, you get None not your default:

>>> dct = dict(foo=123, baz=None) >>> dct.get("foo", 0) 123 >>> dct.get("bar", 0) 0 >>> dct.get("baz", 0) >>> # returns None, not 0 

Since Python 3.8, using the "walrus operator" to create an assignment expression, you can handle this like:

>>> value if (value := dct.get("baz")) is not None else 0 0 

As mentioned elsewhere a possible issue with dct.get(key, default) is that, if key in dct but dct[key] is None, you get None not your default:

>>> dct = dict(foo=123, baz=None) >>> dct.get("foo", 0) 123 >>> dct.get("bar", 0) 0 >>> dct.get("baz", 0) >>> # where'd the value go? 

Since Python 3.8, using the "walrus operator" to create an assignment expression, you can handle this like:

>>> value if (value := dct.get("baz")) is not None else 0 0 

As mentioned elsewhere a possible issue with dct.get(key, default) is that, if key in dct but dct[key] is None, you get None not your default:

>>> dct = dict(foo=123, baz=None) >>> dct.get("foo", 0) 123 >>> str(dct.get("bar", 0) 0 >>> dct.get("baz", 0) >>> # where'd the value go? 

Since Python 3.8, using the "walrus operator" to create an assignment expression, you can handle this like:

>>> value if (value := dct.get("baz")) is not None else 0 0 

As mentioned elsewhere a possible issue with dct.get(key, default) is that, if key in dct but dct[key] is None, you get None not your default:

>>> dct = dict(foo=123, baz=None) >>> dct.get("foo", 0) 123 >>> dct.get("bar", 0) 0 >>> dct.get("baz", 0) >>> # returns None, not 0 

Since Python 3.8, using the "walrus operator" to create an assignment expression, you can handle this like:

>>> value if (value := dct.get("baz")) is not None else 0 0