I was having problems converting a char array like "7c7c7d7d7d7d7c7c7c7d7d7d7d7c7c7c7c7c7c7d7d7c7c7c7c7d7c7d7d7d7c7c2e2e2e" into its actual integer value that would be able to be represented by '7C' as one hexadecimal value. So, after cruising for help i created this, and thought it would be cool to share. This separates the char string into its right integers, and may be helpful to more people than just me ;)

unsigned int* char2int(char *a, int len) { int i,u; unsigned int *val = malloc(len*sizeof(unsigned long)); for(i=0,u=0;i<len;i++){ if(i%2==0){ if(a[i] <= 57) val[u] = (a[i]-50)<<4; else val[u] = (a[i]-55)<<4; } else{ if(a[i] <= 57) val[u] += (a[i]-50); else val[u] += (a[i]-55); u++; } } return val; } 

Hope it helps! Cheers

I was having problems converting a char array like "7c7c7d7d7d7d7c7c7c7d7d7d7d7c7c7c7c7c7c7d7d7c7c7c7c7d7c7d7d7d7c7c2e2e2e" into its actual integer value that would be able to be represented by `7C' as one hexadecimal value. So, after cruising for help I created this, and thought it would be cool to share.

This separates the char string into its right integers, and may be helpful to more people than just me ;)

unsigned int* char2int(char *a, int len) { int i,u; unsigned int *val = malloc(len*sizeof(unsigned long)); for(i=0,u=0;i<len;i++){ if(i%2==0){ if(a[i] <= 57) val[u] = (a[i]-50)<<4; else val[u] = (a[i]-55)<<4; } else{ if(a[i] <= 57) val[u] += (a[i]-50); else val[u] += (a[i]-55); u++; } } return val; } 

Hope it helps!