following is my piece of code which checks if the input format is EMAIL which comes from the form input or not and validates accordingly i want to know how can i modify the following code that validates if the input was only number
if(email.length == 0 || email.indexOf('@') == '-1'){ var error = true; $('#email_error').fadeIn(500); }else{ $('#email_error').fadeOut(500); } 
$(this).jqMethod({ this.nativeMethod()})if (email.match(/[0-9]+/)) { //it's all numbers } EDIT As mentioned in the comments, to ensure that the entry is ALL numbers, the regex would have to include the begin and end characters, ^ and $:
if (email.match(/^[0-9]+$/)) { //it's all numbers } Or even more succinctly:
if (email.match(/^\d+$/)) { //it's all numbers } I don't deserve the credit for that fix, but I did want to correct it for anyone who may come find this later.
isNan(Number(myStr));, but I have a hunch using RegEx will be slower. Plus, I'm biased against RegEx, so that factored into my comment as well.I would use:
if(isNaN(email*1)){ //evaluated to NaN }else{ //evaluated to number } In this case the (email*1) have the possibility to evaluate to NaN, and thus will fail the check because the list of falsish values are 0,"",false,null,undefined,NaN
if(+email)? Minor note/random thought: Huh, there are generally quite a few ways to check if a value is a number in JS.null, so technically it's not a falsy value.
null*1 evaluates to NaN and fail the if() checkif(email*1){ //evaluate to number - which relies on side-effects and needs a comment and $.isNumeric(email) which does not, I would lean towards the isNumeric one...Check if converting the email address to a Number object returns a 'Not a Number' value; if not, the input was a number. The code would look like this:
if(!isNaN(Number(email)) { isNan :)