I want to get the directory where the file resides. For example the full path is:
fullpath = "/absolute/path/to/file" # something like: os.getdir(fullpath) # if this existed and behaved like I wanted, it would return "/absolute/path/to" I could do it like this:
dir = '/'.join(fullpath.split('/')[:-1]) But the example above relies on specific directory separator and is not really pretty. Is there a better way?
You are looking for this:
>>> import os.path >>> fullpath = '/absolute/path/to/file' >>> os.path.dirname(fullpath) '/absolute/path/to' Related functions:
>>> os.path.basename(fullpath) 'file' >>> os.path.split(fullpath) ('/absolute/path/to','file') 
import os.path instead of simply import os?
os.path won't allow me to import os.anything_else (i.e. I need to import os). Found myself wrong when I tried it.