call inline function of another header file from a header file c++

Question

I am having 2 header (.hh) files and there are some functions defined and implemented in both of these files:

What I want it so call a function of the other header file (let's call it B) from an implementation in header file A.

Here is what I have:

//headerA.hh LSQUnit<Impl>::read(...args....) ... callfunction(...args...); }

where the implementation of call function is in the other header file like this:

// headerB.hh template<class Impl> inline void BaseDynInst<Impl>::callfunction (...args...){ .... }

I have added in my headerA.hh these:

#include "headerB.hh" .... void call function (...args...)

but I get undefined reference to callfunction in my headerA.hh

I have also tried these:

when I call it from headerA.hh

callfunction<BaseDynInst> callfunction (...args...)

or add this impleentation of this in my headerB.hh:

LSQUnit<Impl>::callfunction(...args...)

but they gave me more errors.

I know that putting implementations inside .hh may not be ideal but I am using a simulator which is not created by me, so I cannot change that because it will make things worse.

Is it possible what I want or the only solution is to implement the function inside headerA.hh ? I want to avoid that because it calls many others that all exist in headerB.hh?

If you're using templates, then putting implementations inside the header files is mandatory. — Hossein
– Hossein, Commented Apr 30, 2013 at 15:08

stardust · Accepted Answer · 2013-04-30 15:07:34Z

It seems callFunction is a non-static member function of a template class. the corect way to call it is

LSQUnit<Impl> something; something.callFunction(...);

That means you need an object of the class type which owns callFunction. In this case something.

This syntax

LSQUnit<Impl>::callfunction(...args...)

is for calling static member functions.

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