How do I convert a list of ascii values to a string in python?

Same basic solution as others, but I personally prefer to use map instead of the list comprehension:

 >>> L = [104, 101, 108, 108, 111, 44, 32, 119, 111, 114, 108, 100] >>> ''.join(map(chr,L)) 'hello, world' 

import array def f7(list): return array.array('B', list).tostring() 

from Python Patterns - An Optimization Anecdote

You can use bytes(list).decode() to do this - and list(string.encode()) to get the values back.

l = [83, 84, 65, 67, 75] s = "".join([chr(c) for c in l]) print s 

Perhaps not as Pyhtonic a solution, but easier to read for noobs like me:

charlist = [34, 38, 49, 67, 89, 45, 103, 105, 119, 125] mystring = "" for char in charlist: mystring = mystring + chr(char) print mystring 

def working_ascii(): """ G r e e t i n g s ! 71, 114, 101, 101, 116, 105, 110, 103, 115, 33 """ hello = [71, 114, 101, 101, 116, 105, 110, 103, 115, 33] pmsg = ''.join(chr(i) for i in hello) print(pmsg) for i in range(33, 256): print(" ascii: {0} char: {1}".format(i, chr(i))) working_ascii() 

I've timed the existing answers. Code to reproduce is below. TLDR is that bytes(seq).decode() is by far the fastest. Results here:

 test_bytes_decode : 12.8046 μs/rep test_join_map : 62.1697 μs/rep test_array_library : 63.7088 μs/rep test_join_list : 112.021 μs/rep test_join_iterator : 171.331 μs/rep test_naive_add : 286.632 μs/rep 

Setup was CPython 3.8.2 (32-bit), Windows 10, i7-2600 3.4GHz

Interesting observations:

• The "official" fastest answer (as reposted by Toni Ruža) is now out of date for Python 3, but once fixed is still basically tied for second place
• Joining a mapped sequence is almost twice as fast as a list comprehension
• The list comprehension is faster than its non-list counterpart

Code to reproduce is here:

import array, string, timeit, random from collections import namedtuple # Thomas Wouters (https://stackoverflow.com/a/180615/13528444) def test_join_iterator(seq): return ''.join(chr(c) for c in seq) # community wiki (https://stackoverflow.com/a/181057/13528444) def test_join_map(seq): return ''.join(map(chr, seq)) # Thomas Vander Stichele (https://stackoverflow.com/a/180617/13528444) def test_join_list(seq): return ''.join([chr(c) for c in seq]) # Toni Ruža (https://stackoverflow.com/a/184708/13528444) # Also from https://www.python.org/doc/essays/list2str/ def test_array_library(seq): return array.array('b', seq).tobytes().decode() # Updated from tostring() for Python 3 # David White (https://stackoverflow.com/a/34246694/13528444) def test_naive_add(seq): output = '' for c in seq: output += chr(c) return output # Timo Herngreen (https://stackoverflow.com/a/55509509/13528444) def test_bytes_decode(seq): return bytes(seq).decode() RESULT = ''.join(random.choices(string.printable, None, k=1000)) INT_SEQ = [ord(c) for c in RESULT] REPS=10000 if __name__ == '__main__': tests = { name: test for (name, test) in globals().items() if name.startswith('test_') } Result = namedtuple('Result', ['name', 'passed', 'time', 'reps']) results = [ Result( name=name, passed=test(INT_SEQ) == RESULT, time=timeit.Timer( stmt=f'{name}(INT_SEQ)', setup=f'from __main__ import INT_SEQ, {name}' ).timeit(REPS) / REPS, reps=REPS) for name, test in tests.items() ] results.sort(key=lambda r: r.time if r.passed else float('inf')) def seconds_per_rep(secs): (unit, amount) = ( ('s', secs) if secs > 1 else ('ms', secs * 10 ** 3) if secs > (10 ** -3) else ('μs', secs * 10 ** 6) if secs > (10 ** -6) else ('ns', secs * 10 ** 9)) return f'{amount:.6} {unit}/rep' max_name_length = max(len(name) for name in tests) for r in results: print( r.name.rjust(max_name_length), ':', 'failed' if not r.passed else seconds_per_rep(r.time)) 

Question = [67, 121, 98, 101, 114, 71, 105, 114, 108, 122] print(''.join(chr(number) for number in Question))