Python subprocess.popen() without waiting

Question

I'm using Python 3.4.2 on Windows. In script1.py I'm doing this:

myProc = subprocess.Popen([sys.executable, "script2.py", "argument"]) myProc.communicate()

it works and call script2.py . The problem is that in script2.py there is a infinite loop (there must be) and the script1.py is waiting for script2.py to finish. How can I tell to script1.py to just call script2.py and don't wait for the process to finish?

Unrelated: as a more flexible alternative, you could import the script as a Python module instead (use if __name__ =="__main__" guard in it, to avoid running the code on import) and call functions directly or using threading, multiprocessing, concurrent.futures if needed. — jfs
– jfs, Commented Jan 30, 2015 at 14:14

mavroprovato · Accepted Answer · 2015-01-30 09:27:31Z

14

Just don't call myProc.communicate() if you don't want to wait. subprocess.Popen will start the process.

answered Jan 30, 2015 at 9:27

mavroprovato

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1 Comment

jul Over a year ago

I can't believe it..sorry for the silly question, and thanks for the reply.

Iskren · Accepted Answer · 2015-01-30 09:33:06Z

Call the script in another window.

myProc = subprocess.Popen(["start", sys.executable, "script2.py", "argument"]) myProc.communicate()

start is a windows shell function that runs a program separately, allowing the current one to continue its process. I haven't tested this as I've no access to a Windows OS, but The linux equivalent (nohup) works as required.

If you need fine control over what happens with script2.py, refer to the multiprocessing module here.

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