Syntax mistake in php [duplicate]

Question

I don't understand, where the mistake is in this line of code.

$Header .= "<a href='#' onclick='ToggleView(\"Thumbnail\");return false;' title='Grid'><div class='" . if ($Starting_Layout = 'Thumbnail'){ echo 'active';} . " thumb-toggle-icon'></div></a>";

Can someone help me fix it?

What is your error message? I could see 2-3 possible errors. 1. if in assignment. 2. $Starting_Layout is being set, not compared. 3. $Header not initialized. — chris85
– chris85, Commented Sep 21, 2015 at 2:50
It's the if ($Starting_Layout = 'Thumbnail'){ echo 'active';} . Replace this with using short-if: echo ($Starting_Layout = 'Thumbnail' ? "active" : "") — JM R.
– JM R., Commented Sep 21, 2015 at 3:32

John3136 · Accepted Answer · 2015-09-21 02:49:52Z

1

An if statement halfway through your output string? That doesn't look suspicious to you?

answered Sep 21, 2015 at 2:49

John3136

29.3k4 gold badges55 silver badges77 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Syntax mistake in php [duplicate]

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related