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I am writing a UI text in swift under the new Xcode 7 UI test framework. the requirement is to test whether the system keyboard is shown in an app. can someone give me a clue on how to do that? thanks

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  • BTW, when I was trying to look for the accessibility in the debug mode of the keyboard, I can't not see it in the app. so I guess that since it is a system keyboard, so we can not see it Commented Jan 8, 2016 at 19:45

4 Answers 4

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Try this check:

let app = XCUIApplication() XCTAssert(app.keyboards.count > 0, "The keyboard is not shown")

Or check for specific keyboard keys like:

let app = XCUIApplication() XCTAssert(app.keyboards.buttons["Next:"].exists, "The keyboard has no Next button")

You can also control interactions on the keyboard:

let app = XCUIApplication() app.keyboards.buttons["Next:"].tap()
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Add two observers

NSNotificationCenter.defaultCenter().addObserver(self, selector: "keyboardVisible:", name: UIKeyboardDidShowNotification, object: nil) NSNotificationCenter.defaultCenter().addObserver(self, selector: "keyboardHidden:", name: UIKeyboardDidHideNotification, object: nil) func keyboardVisible(notif: NSNotification) { print("keyboardVisible") } func keyboardHidden(notif: NSNotification) { print("keyboardHidden") }

Whenever the keyboard is visible keyboardVisible will be called and whenever the keyboard is hidden keyboardHidden will be called.

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I add this into the UI test code, but it does not work
here is my codeoverride func setUp() { super.setUp() NSNotificationCenter.defaultCenter().addObserver(self, selector: "keyboardDidShow", name: UIKeyboardDidShowNotification, object: XCUIApplication()) }
Should we use NotificationCenter in a UI Test? I doubt it.
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I found the keyboard count check didnt work on one of my apps (it returned a count of 1 even when the keyboard was hidden), so amended it slightly:

private func isKeyboardShown() -> Bool { return XCUIApplication().keyboards.keys.count > 0 }
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could you modify your answer above to read private func... instead of private fund..."
XCUIApplication().keyboards.element(boundBy: 0).exists also works
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extension XCUIApplication { var keyboard: XCUIElement? { let keyboard = keyboards.element(boundBy: 0) return (keyboard.exists && keyboard.isHittable) ? keyboard : nil } var isKeyboardVisible: Bool { keyboard != nil } var isKeyboardHidden: Bool { !isKeyboardVisible } func closeKeyboard() { guard let keyboard else { return } let hideKeyboardButton = keyboard.buttons["Hide keyboard"] if hideKeyboardButton.exists && hideKeyboardButton.isHittable { hideKeyboardButton.tap() } else { let firstKey = keys.element(boundBy: 0) if firstKey.exists { typeText("\n") } } } }
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Please don't post identical answers to multiple questions. Post one good answer, then vote/flag to close the other questions as duplicates. If the question is not a duplicate, tailor your answers to the question. And answers should explain how it solves the issue. Code-only answers are not nearly as useful.

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