I'm trying to split string into Array Of integers:
let stringNumbers = "1 2 10" var arrayIntegers = stringNumbers.characters.flatMap{Int(String($0))} But my problem is I'm getting this output:
[1, 2, 1, 0] When I should be getting this output:
[1, 2, 10] What I'm doing wrong?
I'll really appreciate your help.
Use this
let stringNumbers = "1 2 10" let array = stringNumbers.components(separatedBy: " ") let intArray = array.map { Int($0)!} // [1, 2, 10] 
!. While it won't cause problems with this specific string, it will crash if the string actually contains any text that can't be converted to a number.
You are converting the individual characters of the strings into numbers. First the 1, then the space, then the 2, then the space, then the 1, and lastly the 0. If course converting the space gives a nil with is filtered out by using flatMap.
You can do:
let stringNumbers = "1 2 10" var arrayIntegers = stringNumbers.components(separatedBy: " ").flatMap { Int($0) } This splits the original string into an array of strings (separated by a space) and then maps those into integers.
let arrayIntegers = stringNumbers.components(separatedBy: " ").flatMap{ Int($0) }map will give an array of optionals in this case. And using flatMap leaves out any nil values if the string contains any text that can't be converted to a number.
?? with flatMap. And Int will never be a String so it makes no sense at all.In Swift 5 it is:
let stringNumbers = "1 2 10" var arrayIntegers = stringNumbers.split(separator: " ").compactMap { Int($0) } 
stringNumbers.components(separatedBy: .whitespaces).compactMap { Int($0) }. You can also use .whitespacesAndNewlines to split by newlines too.