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I have following two lines in Java code :

String str = new String("My place") String str1 = new String("My place")

It is clear that new String("My place") creates two object,one due to interning and another due to new but i am confused as here the argument is having same literal so whether same interned object is being used by str1 resulting in 3 objects or different resulting in 4 objects

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    3 objects...because of the literal being the same. Commented Mar 23, 2017 at 10:29

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Interning of string literals is automatic in Java, so the same interned object will be used in both constructors, so there will be three objects, not four.

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same interned object will be used by str1 resulting in 3 objects , try to undertnad using equals methods

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str1 has nothing to do with interning, and what exactly does the equals() method have to do with the question?
let's assume class String has a field, private char[] data. Then after String str= new String("xyz"); the following will be true: str.equals("xyz"), str != "xyz", str.data == "xyz".data. I.e. both fields refer to the same array.My point is use equals() and == method to understand object creation in string pool and heap.

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