I am executing a jar file from another jar file. While accessing resources file from child jar it is giving exception : java.io.FileNotFoundException: File 'file:PATH_TO_CHILD_JAR/example-1.0.0-0-SNAPSHOT-jar-with-dependencies.jar!resource_file_path/abs.sql.tpl' does not exist.
I am not able to figure why it is taking "!" mark while searching for resource files.
you can execute the jar file with in java program.
make sure that you have added Manifest file in the jar which has Main-Class attribute.
My steps and output:
Created manifest file with the following line: Main-Class: com.demo.TestJar
Created Test Java program:
package com.demo; public class TestJar extends Object { public static void main(String args[]) { System.out.println("TestJar"); } } Package the jar : jar cvfm /home/user/TestJarOne.jar manifest.txt
Write test program:
import java.io.BufferedInputStream; import java.io.IOException; public class TestJSS extends Object { static int i = 0; public static void main(String args[]) throws IOException, InterruptedException { System.out.println("Calling jar"); Process p = Runtime.getRuntime().exec("java -jar /home/user/TestJarOne.jar arg1 arg2"); BufferedInputStream bis = new BufferedInputStream(p.getInputStream()); synchronized (p) { p.waitFor(); } System.out.println(p.exitValue()); int b=0; while((b=bis.read()) >0){ System.out.print((char)b); } System.out.println(""); System.out.println("Called jar"); } }
Try this
// Run a java app in a separate system process Process proc = Runtime.getRuntime().exec("java -jar A.jar"); // Then retreive the process output InputStream in = proc.getInputStream(); InputStream err = proc.getErrorStream(); 