How to convert a list of characters to ASCII in python?

You might use a list comprehension, like so:

string = input(“Enter a line of text: “) list_of_characters = list(string) list_of_ord_values = [ord(character) for character in list_of_characters] 

Note that, since strings are iterable, you can skip the intermediate step:

list_of_ord_values = [ord(character) for character in string] 

string = input("enter string: ") for i in string: if i != ' ': # ignoring space char print(i, ord(i)) 

Input

sample string 

Output

s 115 a 97 m 109 p 112 l 108 e 101 s 115 t 116 r 114 i 105 n 110 g 103 

The output can even be saved to another list.

You need to make a for loop to loop over each character and convert them to ASCII.

You already have l which is a list of each character in the string. So loop over l and convert each character in the list to the ASCII value using ord().

Here's a time complexity efficient way of doing it. Assuming your list is of single characters as such:

l = ['a', 'b', 'c'] ascii_values = map(ord, l)

This will map each character to its specified ascii value.

If you are using python 2, strings are encoded as ascii by default. If you are using python 3, you can convert a string to ascii using the built-in string method encode:

ascii = string.encode('ascii') 

If you want this to be represented as a list, you might try encoding each separately, as the default iterated representation for ascii characters are integers. (try [x for x in b'binary string!'])

ascii_chars = [char.encode('ascii') for char in string]