I get an issue using REGEX, it is probably about my REGEX but I need some helps.
I need to match all string containing "D"...
Test string 1 : D Test string 2 : aaaaaaDqqqqq Test string 3 : Dssssssss Test string 4 : D4564646 Test string 5 : 1321313D2312 Test string 6 : ppppprrrrrr My regex :
/^.+D.+|(:?^|\s)D$/gi It works only for 1 and 2 and it should works for 1, 2, 3, 4 and 5.
In your case problem is with + operator which is literally Matches between one and unlimited times so it wont work if letter "D" will be in the beggining or the end of string. Try this regex: ^.*D.*$ with asterix, as it is defined as Matches between zero and unlimited times
^.*D.*$ is inefficient and will choke on multiline input. Do not use it.Following regex should work for you
.*D.* 
.*D.* is inefficient and will choke on multiline input. Do not use it.If all you need to do is test for whether or not a string contains a D character, it's just /D/
var tests = [ "D", "aaaaaaDqqqqq", "Dssssssss", "D4564646", "1321313D2312", "ppppprrrrrr" ] tests.forEach(str => console.log(/D/.test(str)))Instead of using a regex simply use the includes function
var string = "aaaaaaDqqqqq", substring = "D"; if(string.includes(substring)){ console.log("contain") }else{ console.log("don't contain") }
^.*D.*$? Or[^D]*D[\s\S]*..*.indexOforincludes, which is a more natural way to check if a char exists in an input string in JavaScript.