-2

The question look like this

https://i.imgur.com/u0LJO0g.png

where do i get wrong?

#include<stdio.h> int main(){ int i,n; int a[] = {3,5,7}; float x[] = {0,0,0}; printf("function f(x)=(x^3-2x^2+10x-5)/(x-10)\n"); for(i = 0;i<3;i++){ x[i] = (a[i]^3-2*(a[i]^2)+10*a[i]-5)/(a[i]-10); } for(n = 0;n<3;n++){ printf("if x is %d,f(x) is %f\n",a[n],x[n]); } }

I expect the output will look that this

if x is 3,f(x) is -5.14 if x is 5,f(x) is -24.00 if x is 7,f(x) is -103.33

but the actual output is

if x is 3,f(x) is -3.000000 if x is 5,f(x) is -7.000000 if x is 7,f(x) is -20.000000
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    You need to review operators in C as well as being aware of the difference between integer division and floating point division. The ^ operator does not raise a number to a power in C. In C ^ is the exclusive OR (XOR) operator. Commented Sep 20, 2019 at 17:17

1 Answer 1

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  1. ^ is XOR in C, not exponentiation.
  2. If you do math on ints you're going to get int results. You'll need to cast some of those a[i] to float or double to get floating point arithmetic.
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