I know this is kind of a hacky thing I'm trying here, but I'm wondering if this is even possible. is there anyway I can access the $x variable in the following code, without passing arguments?
function foo() { $x = 1; return bar(); } function bar() { //get $x from foo here somehow? return $x ? 'stuff' : 'other stuff'; } I am not sure why, but you can use globals that opens up to a whole thing, but i will show you:
function foo() { global $x; $x = 1; return bar(); } function bar() { global $x; //get $x from foo here somehow? return $x ? 'stuff' : 'other stuff'; } Here is the demo: http://codepad.org/fPqUXzyC
It is always better to not use globals and just pass parameters, but if you cannot you could use globals
uplevel type of functionality.
suspect anything, how do you know?global statement creates $x in the global scope.class baz { private $x; public function foo() { $this->x = 1; return $this->bar(); } public function bar() { return $this->x ? 'stuff' : 'other stuff'; } } You could make foo() store the $x value to $GLOBALS[] or global $x;. Other than that, nothing I can think of would do it. It would need to be purposely exposed to get it from inside another function.
If this is your code, I may recommend thinking about taking an object-oriented approach.
class Foo { public static $x; public static function Foo(){ Foo::$x = 1; return Foo::Bar(); } public static function Bar() { return Foo::$x ? 'stuff' : 'other stuff'; } } echo Foo::Foo(); Alternatively, do as others have suggested and pass $x as a function parameter.
I know this is kind of old, and an answer has already been accepted, but wouldn't this work?
function foo() { $x = 1; return bar($x); } function bar($x) { return $x ? 'stuff' : 'other stuff'; } 
bar() function. so no, this would not work in this scenario.